Showing Linearity of $\varphi$ for $K(a)$

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SUMMARY

The discussion focuses on demonstrating the linearity of the map $\varphi : K(a) \rightarrow K(a)$ defined by $\varphi(e) = ae$ for a field extension $K \leq K(a)$ with $[K(a):K]=n$. To establish that $\varphi$ is a $K$-linear map, one must verify the condition $\varphi(te + e') = t\varphi(e) + \varphi(e')$ for all $t \in K$ and $e, e' \in K(a)$. Additionally, the characteristic polynomial of $\varphi$ is identified as $p(x) = \text{det}(x1_{K(a)} - \varphi)$, where the map $x1_{K(a)}$ sends $e \in K(a)$ to $xe$.

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mathmari
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Hey! :o

Let $K \leq K(a)$ a field extension with $[K(a):K]=n$.

$K(a)$ is a vector space over $K$.

How can I show that the map $\varphi : K(a) \rightarrow K(a)$, with $\varphi(e)=ae$, is a $K-$linear map??
 
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mathmari said:
Hey! :o

Let $K \leq K(a)$ a field extension with $[K(a):K]=n$.

$K(a)$ is a vector space over $K$.

How can I show that the map $\varphi : K(a) \rightarrow K(a)$, with $\varphi(e)=ae$, is a $K-$linear map??

Hi mathmari,

To show that $\varphi$ is $K$-linear, you must verify

$$ \varphi(te + e') = t\varphi(e) + \varphi(e') \quad \text{for all} \quad t\in K, \, e, e'\in K(a).$$
 
Euge said:
Hi mathmari,

To show that $\varphi$ is $K$-linear, you must verify

$$ \varphi(te + e') = t\varphi(e) + \varphi(e') \quad \text{for all} \quad t\in K, \, e, e'\in K(a).$$

I understand! Thank you! (Sun)

I have also an other question...

I am also asked to show that $a$ is a root of the characteristic polynomial of $\varphi$.

Which is the characteristic polynomial of $\varphi$?? (Wondering)
 
mathmari said:
I understand! Thank you! (Sun)

I have also an other question...

I am also asked to show that $a$ is a root of the characteristic polynomial of $\varphi$.

Which is the characteristic polynomial of $\varphi$?? (Wondering)

It's $p(x) = \text{det}(x1_{K(a)} - \varphi)$. The map $x1_{K(a)} - \varphi$ sends $e \in K(a)$ to $xe - ae$.
 
Euge said:
It's $p(x) = \text{det}(x1_{K(a)} - \varphi)$. The map $x1_{K(a)} - \varphi$ sends $e \in K(a)$ to $xe - ae$.

Could you explain me what $x1$ is ?? (Wondering)
 
mathmari said:
Could you explain me what $x1$ is ?? (Wondering)

The map $x1_{K(a)}$ sends $e\in K(a)$ to $xe$.
 

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