Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Showing skew lines lie in parallel planes

  1. Jul 16, 2009 #1
    Im givin these two lines..
    L1= x=4+5t y=5+5t z=1-4t
    L2= x=4+s y=-6+8s z=7-3s

    What i tried doing was taking the directional vector of both lines <5 5 -4> <1 8 -3>, and crossing them to find the normal vector. I hav enough information to find 1 equation of a plane, but how can I find the other. Can someone please point me in the right direction. Thanks in advance!
  2. jcsd
  3. Jul 16, 2009 #2


    User Avatar
    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi mikemichiel! Welcome to PF! :wink:
    You have the normal …

    can't you find the plane from that?

    And why do you need more than 1 equation for a plane? :smile:
  4. Jul 16, 2009 #3


    User Avatar
    Science Advisor

    To find the equation of a plane, you need a normal vector and a point in the plane. You have two lines that presumably lie in each line in the planes you want. Any point on the line will do.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook