Sign of Area Under Velocity v. Time Graph: Help Me!

  • Thread starter Thread starter bigbasherboy
  • Start date Start date
Click For Summary
SUMMARY

The discussion clarifies the physical meaning of the area under velocity versus time and acceleration versus time graphs. The area under a velocity-time graph represents displacement, with positive values indicating movement in the positive direction and negative values indicating movement in the negative direction. Similarly, the area under an acceleration-time graph signifies the change in speed, where positive areas indicate an increase in speed and negative areas indicate a decrease. The concept of signed area is crucial, as negative displacement corresponds to areas graphed below the x-axis.

PREREQUISITES
  • Understanding of basic kinematics concepts
  • Familiarity with graph interpretation in physics
  • Knowledge of integral calculus for area calculation
  • Concept of signed area in mathematical contexts
NEXT STEPS
  • Study the relationship between velocity and displacement in kinematics
  • Learn about the integral calculus applications in physics
  • Explore graphical representations of motion in physics
  • Investigate the implications of negative values in physical graphs
USEFUL FOR

Students of physics, educators teaching kinematics, and anyone interested in understanding motion through graphical analysis.

bigbasherboy
Messages
3
Reaction score
0
:confused: what is the physical meaning of the sign of the area under a velocity v. time graph (displacement) ??

what is the physical meaning of the sign of the area under a acceleration
v. time graph (velocity) ??

:confused:
please help me
 
Last edited:
Physics news on Phys.org
I'm not quite sure what you mean: area is always positive. Assuming you mean "signed" area (a bit of a strange terminology), the area under the velocity v time graph is "displacement"- distance moved. If that is positive, then you have moved in the positive direction, if negative you have moved in the negative direction.

"Area" under the acceleration v time graph is change in speed. If that is positive, speed has increased, if negative, speed has decreased.
 
ok i see, but let's say we have negitive displacement, does that mean the "area" would be graphed below the x-axis on a graph ?
 
bigbasherboy said:
ok i see, but let's say we have negitive displacement, does that mean the "area" would be graphed below the x-axis on a graph ?
Yes, because velocity "v" would be negative ("under the x-axis"), and the integral would yield a negative value (or "area") for displacement.


~~
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
609
  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
25
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
7
Views
2K