Significant figures -- wrong answer to Thermodynamics question?

Click For Summary
The discussion centers on the appropriate use of significant figures in a thermodynamics problem where the calculated heat, Q, is 54,500 J. There is debate about whether the final answer should be rounded to one significant figure, resulting in 60,000 J, due to the initial volume's precision. Participants highlight that the precision of chart values could influence the significant figures, with some values possibly having more significant figures than initially considered. Additionally, there is a mention of the conversion factor between atmospheres and pascals affecting the overall precision. The conversation emphasizes the importance of accurately interpreting significant figures based on the data provided.
member 731016
Homework Statement
I am confused why the answer to the problem below has more significant figures than it should.
Relevant Equations
##\Delta E_{int} = Q - W##
For this problem,
1680317487199.png

The solution is, ## Q = 54500 J ## , however, since the calculation for heat uses the first law which involves ##5 \times 10^{-3) m^3 ## value for the initial volume, should the finial answer not be to 1 sig fig as well? This would give ## 60000 J ##.

Many thanks!
 

Attachments

  • 1680317595556.png
    1680317595556.png
    421 bytes · Views: 128
Physics news on Phys.org
Whether it is ##5\cdot 10^{-3}##, ##5.0\cdot 10^{-3}##, ##5.00\cdot 10^{-3}## etc. depends on how precisely you think you can read it off the chart. Similarly the other chart readings. The more limiting precision would be the 30kJ.
 
  • Like
Likes member 731016
haruspex said:
Whether it is ##5\cdot 10^{-3}##, ##5.0\cdot 10^{-3}##, ##5.00\cdot 10^{-3}## etc. depends on how precisely you think you can read it off the chart. Similarly the other chart readings. The more limiting precision would be the 30kJ.
Thank you for your reply @haruspex!

True you make a very valid point! I had not considered that the chart values could have more sig figs that they point.
 
I think they expect you to observe that at 5 l, the pressure is 50 atm and at 12 l, the pressure is 20 atm, (exactly). They apparently took the conversion between atm and Pa to be 1.00000 rather than 101325.
 
  • Like
Likes member 731016
Chestermiller said:
I think they expect you to observe that at 5 l, the pressure is 50 atm and at 12 l, the pressure is 20 atm, (exactly). They apparently took the conversion between atm and Pa to be 1.00000 rather than 101325.
Thank you for reply @Chestermiller !
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 19 ·
Replies
19
Views
7K
Replies
7
Views
2K
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
25
Views
1K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K