Significant figures -- wrong answer to Thermodynamics question?

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Homework Help Overview

The discussion revolves around the application of significant figures in a thermodynamics problem involving heat calculation and volume measurements. Participants are examining how the precision of various values affects the final answer.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning how the precision of the initial volume measurement influences the significant figures in the final answer. There is also discussion about the precision of chart readings and their impact on calculations.

Discussion Status

Some participants have offered insights regarding the precision of measurements and how they relate to significant figures. Multiple interpretations of the problem are being explored, particularly concerning the values derived from charts and their implications for the calculations.

Contextual Notes

There is mention of specific values from charts and their potential precision, as well as a reference to the conversion factor between atm and Pa, which may affect the calculations. The discussion highlights the need to consider how these factors influence the final result.

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Homework Statement
I am confused why the answer to the problem below has more significant figures than it should.
Relevant Equations
##\Delta E_{int} = Q - W##
For this problem,
1680317487199.png

The solution is, ## Q = 54500 J ## , however, since the calculation for heat uses the first law which involves ##5 \times 10^{-3) m^3 ## value for the initial volume, should the finial answer not be to 1 sig fig as well? This would give ## 60000 J ##.

Many thanks!
 

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Whether it is ##5\cdot 10^{-3}##, ##5.0\cdot 10^{-3}##, ##5.00\cdot 10^{-3}## etc. depends on how precisely you think you can read it off the chart. Similarly the other chart readings. The more limiting precision would be the 30kJ.
 
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haruspex said:
Whether it is ##5\cdot 10^{-3}##, ##5.0\cdot 10^{-3}##, ##5.00\cdot 10^{-3}## etc. depends on how precisely you think you can read it off the chart. Similarly the other chart readings. The more limiting precision would be the 30kJ.
Thank you for your reply @haruspex!

True you make a very valid point! I had not considered that the chart values could have more sig figs that they point.
 
I think they expect you to observe that at 5 l, the pressure is 50 atm and at 12 l, the pressure is 20 atm, (exactly). They apparently took the conversion between atm and Pa to be 1.00000 rather than 101325.
 
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Chestermiller said:
I think they expect you to observe that at 5 l, the pressure is 50 atm and at 12 l, the pressure is 20 atm, (exactly). They apparently took the conversion between atm and Pa to be 1.00000 rather than 101325.
Thank you for reply @Chestermiller !
 

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