Simple but tricky problem, horizontal motion

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    Horizontal Motion
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SUMMARY

The problem involves a cannonball shot horizontally at a target, striking 0.2 meters below the bullseye with an initial speed of 956 m/s. To solve for the horizontal distance (D_x), first calculate the time (t) it takes for the cannonball to fall 0.2 meters using the formula for vertical displacement under gravity. Once t is determined, use it to find the horizontal distance by applying the formula D_x = initial speed * t. This approach effectively combines kinematic equations for projectile motion.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Basic knowledge of projectile motion
  • Familiarity with gravitational acceleration (9.81 m/s²)
  • Ability to perform calculations involving horizontal and vertical components of motion
NEXT STEPS
  • Calculate vertical displacement using the formula D_y = 0.5 * g * t²
  • Determine time of flight (t) from the vertical displacement
  • Apply the horizontal motion formula D_x = initial speed * t
  • Explore graphical representations of projectile motion
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone preparing for exams in mechanics or kinematics.

phynoob
Im studying for my test and I have a problem from my previous notes. It should be simple but I am having some difficulty.

''
A cannon is shooting horizontally at a target. The cannonball strikes .2m below the bullseye. If the initial speed of the cannonball is 956m/s, what is the distance?
''

Any help would be appreciated.
 
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Draw a picture of what it looks like, include the path if there was no gravity and then draw the actual path. You are solving for D_y that should be plenty to get you started.
 
Find the value of t from the vertical displacement. Then find horizontal distance by using the value.
 

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