Simple challenging fluid mechanics question(buoyancy)

Click For Summary

Discussion Overview

The discussion revolves around a fluid mechanics question regarding the buoyancy of a steel block floating in mercury. Participants explore how cutting a portion of the block affects the pressure on its lower surface when re-immersed in mercury. The scope includes theoretical reasoning and interpretations of buoyancy principles.

Discussion Character

  • Exploratory
  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants assert that the pressure on the lower surface of the block will be lower in the second state due to the reduced weight of the block after cutting.
  • Others propose that the pressure could be equal in both states under specific conditions, particularly if the cut allows mercury to flow into the removed section.
  • A participant suggests that if the cut dimensions are very close to the original dimensions, the pressure could be approximated as equal, though not truly equal.
  • Another participant emphasizes that removing material from the block will inherently lead to lower pressure, regardless of the specifics of the cut.

Areas of Agreement / Disagreement

Participants express differing views on how cutting the block affects pressure, with some agreeing that pressure decreases while others argue for conditions under which it may remain approximately equal. The discussion remains unresolved with multiple competing perspectives.

Contextual Notes

Participants highlight assumptions regarding the flow of mercury into the cut section and the specific dimensions of the cuts, indicating that these factors could influence the pressure outcomes but are not definitively resolved.

farhad_mech
Messages
12
Reaction score
0
hello fluid knowers!
here is a question i have asked from several students every time a different answer was given to me.
now let's see what is your answer mechanicals!

question:
we have a steel block floating in mercury as shown below:
http://www.pikipimp.com/pp/pimped_photo/s/image/41/662/573/1.JPG?ts=1235241467627

now we bring the block out of mercury and cut a piece of block for example EFHG and then again put it in the mercury,the question is how pressure on the lower surface of block named CD changes?
here is possible answers:
-it is equal in both states
-it is lower in second state
-it is lower in first state
-it depends on how we cut the block
 
Last edited by a moderator:
Engineering news on Phys.org
It is lower in the second state. Basically, you have a block with the same dimensions and a lower weight in the second state than in the first. It floats higher and the pressure on the bottom surface is lower.
 
you were near the right answer but i have another opinion, i will give it away tonight.
 
Russ is right. Its a simple statics problem. Less weight means there is less mass to be supported against gravity and since the geometry of CD didn't change the pressure will be lower.
 
Second way the pressure would be less.
 
i can confirm that your answers were right,but i think there is an exception,if you cut the piece in this way:
-EF and HG can have any length
-Eh and FG are cut so that their length is equal to AC or BD,i mean if AC and BD are for example 1 [m],EH and FG are cut so that their length is 0.99999 [m]
in this way the pressure would be very very near to first state and we can take them equal.
what's your opinion?
 
They can be approximated to be equal but are not.
 
farhad_mech said:
i can confirm that your answers were right,but i think there is an exception,if you cut the piece in this way:
-EF and HG can have any length
-Eh and FG are cut so that their length is equal to AC or BD,i mean if AC and BD are for example 1 [m],EH and FG are cut so that their length is 0.99999 [m]
in this way the pressure would be very very near to first state and we can take them equal.
what's your opinion?
If the slot is cut such that mercury can flow into this cut slot, then if you do what you're suggesting, then yes, the pressure is effectively the same with only some small deviation due to the volume of material left between the two remaining sections.

I think that looking at your diagram, it is assumed that mercury won't ever be able to enter this volume (EFGH) that was removed. If that were the case, then the block would only ever float higher and result in lower pressure.
 
Thats a pretty ******** ambiguous question if you ask me.

Very very near does not make them equal. Bottom line remove material = lower pressure.

And for another thing cutting EH to = AC would remove that section ACEH from the main block.
 
Last edited:

Similar threads

  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 19 ·
Replies
19
Views
6K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
11K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K