MHB Simple closed form for integral

Click For Summary
The discussion revolves around finding a closed form for the integral involving trigonometric and logarithmic functions. The integral in question is $$\int_{0}^{1}t\cos(2t\pi)\tan(t\pi)\ln[\sin(t\pi)]\mathrm dt$$ and is proposed to equal $$\frac{1}{\pi}\cdot\frac{\ln 2}{2}(1-\ln 2)$$. Participants express a desire for hints to approach the solution, indicating a lack of progress over time. The request for assistance remains unanswered after multiple follow-ups. The conversation highlights the challenge of solving complex integrals in mathematical analysis.
Tony1
Messages
9
Reaction score
0
How may we go about to show that,

$$\int_{0}^{1}t\cos(2t\pi)\tan(t\pi)\ln[\sin(t\pi)]\mathrm dt=\color{green}{1\over \pi}\cdot\color{blue}{{\ln 2\over 2}(1-\ln 2)}$$
 
Mathematics news on Phys.org
A hint is requested ... (Blush)
 
lfdahl said:
A hint is requested ... (Blush)
can I get the hint?
 
64 days after my 1st request:

A hint is still requested ... (Wave)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K