- #1
Sirsh
- 267
- 10
I have the equation:
x = 2*L*sin(θ/2) and in my lecture notes they have converted it to: ϑx = L*cos(θ/2)*ϑθ
Is it correct to do the following to get this answer?
x = 2*L*sin(θ/2)
x = 2*L*sin(θ/2)*(ϑ(θ/2)/ϑx)
x*ϑx = 2*L*sin(θ/2)*ϑ(θ/2)
1*ϑx = (1/2)*2*L*cos(θ/2)*ϑθ
ϑx = L*cos(θ/2)*ϑθ
My problem is I don't see how you can keep ϑx and ϑθ after the differentiation operation has been done, and if it is correct to be able to separate ϑ(θ/2) into (1/2)*ϑθ ?
Any help would be appreciated, Thanks.
x = 2*L*sin(θ/2) and in my lecture notes they have converted it to: ϑx = L*cos(θ/2)*ϑθ
Is it correct to do the following to get this answer?
x = 2*L*sin(θ/2)
x = 2*L*sin(θ/2)*(ϑ(θ/2)/ϑx)
x*ϑx = 2*L*sin(θ/2)*ϑ(θ/2)
1*ϑx = (1/2)*2*L*cos(θ/2)*ϑθ
ϑx = L*cos(θ/2)*ϑθ
My problem is I don't see how you can keep ϑx and ϑθ after the differentiation operation has been done, and if it is correct to be able to separate ϑ(θ/2) into (1/2)*ϑθ ?
Any help would be appreciated, Thanks.