Simple Harmonic Motion of Charges

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SUMMARY

The discussion centers on the analysis of simple harmonic motion (SHM) of a negatively charged particle -q placed at the center of a uniformly charged ring with positive charge Q. The derived frequency of oscillation is given by the formula f = (1/2π)(kqQ/ma^3)^(1/2). The participant initially attempted to calculate the net force on the particle using Coulomb's law and torque equations but encountered discrepancies in the final frequency expression. Clarification on the orientation of the charged ring relative to the x-axis is necessary for accurate calculations.

PREREQUISITES
  • Understanding of Coulomb's Law (F = kq1q2/r^2)
  • Familiarity with torque and moment of inertia concepts
  • Knowledge of angular frequency and simple harmonic motion
  • Basic calculus for limits and derivatives
NEXT STEPS
  • Review the derivation of simple harmonic motion equations in electrostatics
  • Study the effects of charge distribution on force calculations
  • Learn about the orientation of charged bodies in three-dimensional space
  • Explore the relationship between torque and angular motion in physics
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism and mechanics, as well as anyone involved in solving problems related to simple harmonic motion of charged particles.

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Homework Statement


A negatively charged particle -q is placed at the center of a uniformly charged ring of radius a having positive charge Q. The particle, confined to move along the x-axis, is moved a small distance x along the axis (x << a) and released. Show that th eparticle oscillates in simple harmonic motion with a frequency given by
f = (1/2pi)(kqQ/ma^3)^(1/2).


Homework Equations


F = kq1q2/r^2
torque = r x F
torque = (I)(alpha)
I (moment of inertia) = mL^2 (L = distance from point about which rotation occurs, in this case, approx. L = a)
alpha = d^2(theta)/dt^2
*Where theta is angle between a and the hypotenuse in the triangle with base and height a and x.


The Attempt at a Solution


I tried finding net force on -q as exerted by the ring (relevant force is only in x direction)
F = -kQq/a(a-x) + kQq/a(a+x)
F = -2kQqx/a^3

then I plugged this into torque = r x F
where r is approx. a
and equated with torque = I(alpha)
which gave me the motion for simple harmonic motion d^2(theta)/dt^2 + 2kQqx(theta)/ma^4
(I made use of the limit lim(∆theta-->0) sin(theta)/theta = 1)

and from this, the angular frequency should be (2kQqx/ma^4)^(1/2)
which gives f = (1/2(pi))(kQqx/ma^4)^(1/2)
which obviously isn't the answer.

What am I doing wrong?

 
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It appears what you're doing wrong is blindly using formulas without understanding what they mean.

You didn't explain how the ring is oriented relative to the x-axis. Does it lie in the yz-plane with its center at the origin?
 

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