I did an approximation by hand,
Take the first terms of taylor series for sine
[tex]sin(x) = x - \frac { x^3 } {6} + \frac {x^5} {120}[/tex]
[tex]\frac { \sin x } {x} = 1 - \frac { x^2 } {6} + \frac {x^4} {120} = 0.99[/tex]
[tex]x^4 - 20x^2 + 1.2 = 0[/tex]
Substitute, a = x^2
[tex]a^2 - 20a + 1.2 = 0[/tex]It's an easy quadratic equation, also got 0.2459674, and other solution 4.465366 which doesn't work.