Simple inductance question: Finding steady state current

Click For Summary
SUMMARY

The discussion centers on understanding the behavior of inductors in electrical circuits, specifically regarding steady-state current and the relationship between current and potential difference across an inductor. It is established that when current is split evenly between two paths with equal resistance, the inductor's resistance is negligible, leading to equal current distribution. The potential difference across the inductor becomes zero when the rate of change of current (dI/dt) approaches zero, confirming that both the EMF and potential difference are directly linked to changes in current.

PREREQUISITES
  • Basic understanding of electrical circuits and Ohm's Law (I = E / R_total)
  • Familiarity with inductors and their role in circuits
  • Knowledge of the relationship between current, voltage, and resistance
  • Understanding of the concept of EMF and its relation to changing current (E = -L dI/dt)
NEXT STEPS
  • Study the principles of inductors and their applications in AC and DC circuits
  • Learn about the behavior of inductors in transient analysis
  • Explore the relationship between inductance and energy storage in magnetic fields
  • Investigate practical applications of inductors in filters and oscillators
USEFUL FOR

Electrical engineering students, hobbyists working with circuits, and professionals involved in circuit design or analysis will benefit from this discussion on inductors and steady-state current behavior.

alexdr5398
Messages
31
Reaction score
1

Homework Statement


n61jULN.jpg


Homework Equations


I = E / R_total

The Attempt at a Solution


I mostly just want to clarify that my thinking is correct. The solution for this problem shows that the current is split evenly between the two paths. Is that because we're assuming that the inductor has no resistance? So since both paths have resistance R, they both draw the same current?

Also, the solution states that the potential different across the inductor goes to zero as dI/dt goes to zero. Why does the current through L not also go to zero? Since:

I_L = E_L / R = 0 / R = 0
 
Physics news on Phys.org
alexdr5398 said:
I mostly just want to clarify that my thinking is correct. The solution for this problem shows that the current is split evenly between the two paths. Is that because we're assuming that the inductor has no resistance?
Yes.
So since both paths have resistance R, they both draw the same current?
Yes. To be more pedantically correct, they both pass or conduct the same current since they share the same potential difference and have the same resistance.
Also, the solution states that the potential different across the inductor goes to zero as dI/dt goes to zero. Why does the current through L not also go to zero? Since:

I_L = E_L / R = 0 / R = 0
As you've stated, the inductor does not have resistance, and certainly not a value of R. Also, E_L is across the inductor only, it doesn't include the series connected resistor that shares its path. that resistance will have its own potential difference due to the current flowing through it.
 
Thank you, that makes sense.
gneill said:
Also, E_L is across the inductor only, it doesn't include the series connected resistor that shares its path.

I don't really understand what inductors are or how they work very well. I just know that they have something to do with changes in current. Is the solution stating that because dI/dt goes to zero, the potential difference across the inductor goes to zero? Or just that both of them go to zero?
 
alexdr5398 said:
Thank you, that makes sense.I don't really understand what inductors are or how they work very well. I just know that they have something to do with changes in current. Is the solution stating that because dI/dt goes to zero, the potential difference across the inductor goes to zero? Or just that both of them go to zero?
Inductors react to a change in current by producing an EMF that tries to counter the change. That's what the equation ##E = -L~dI/dt## is saying. The analogy in mechanics is that of a mass that resists a change in velocity thanks to inertia, thus the so-called "inertial force" that makes up the Newton's third law reaction force. The formula there is ##F = -M~dV/dt##.

When the current through an inductor is constant so that dI/dt is zero there is no EMF produced. The potential difference across that inductor will be zero for any given constant current. So the two things, zero EMF and zero dI/dt are intimately related. The solution is stating that because dI/dt goes to zero, the potential difference across the inductor goes to zero, as you have written.
 
  • Like
Likes alexdr5398
gneill said:
Inductors react to a change in current by producing an EMF that tries to counter the change. That's what the equation ##E = -L~dI/dt## is saying. The analogy in mechanics is that of a mass that resists a change in velocity thanks to inertia, thus the so-called "inertial force" that makes up the Newton's third law reaction force. The formula there is ##F = -M~dV/dt##.

When the current through an inductor is constant so that dI/dt is zero there is no EMF produced. The potential difference across that inductor will be zero for any given constant current. So the two things, zero EMF and zero dI/dt are intimately related. The solution is stating that because dI/dt goes to zero, the potential difference across the inductor goes to zero, as you have written.

Alright, I understand now, thank you!
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 10 ·
Replies
10
Views
904
  • · Replies 10 ·
Replies
10
Views
2K
Replies
18
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K