Simple kinematics problem: avg. acceleration if a car's going 12 m/s and accel

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SUMMARY

The discussion centers on calculating average acceleration for a car initially traveling at 12 m/s, which accelerates at 1.7 m/s² for 12 seconds. The average acceleration is derived using the formula a = (change in velocity)/time, where the final velocity after acceleration is 32.4 m/s. The average speed is then calculated by averaging the initial speed of 12 m/s and the final speed of 32.4 m/s, resulting in an average speed of 22.2 m/s. The participant initially struggled with visualizing the problem but ultimately clarified their understanding of the concepts involved.

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  • Understanding of basic kinematics principles
  • Familiarity with acceleration and velocity formulas
  • Knowledge of graphing speed versus time
  • Ability to perform basic arithmetic operations with units
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  • Study the kinematic equations, particularly v = vi + at
  • Learn how to graph motion with constant speed and acceleration
  • Explore average speed calculations in physics
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Students studying physics, particularly those focusing on kinematics, as well as educators seeking to clarify concepts of acceleration and average speed.

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A basic kinematics problem that I just can't get for some reason. I'm having trouble visualizing the graph.

Homework Statement


What's the average acceleration if a car's going 12 m/s constant speed, then accelerates for 12 seconds at 1.7 m/s^2 acceleration?
Variables: none?

Homework Equations


? I do not know. At all.

The Attempt at a Solution


I had graphed speed over time with the function as a horizontal line until it reached the origin, where it gained a slope of 1.7 because of the acceleration. I don't know if I'm visualizing the increase in speed correctly or if it would become an exponential curve. If this was the result, I don't know how I would then find average speed--total distance over time. Would I need to know calculus to figure this out? So this is where I'm stuck.
 
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Missing information - it doesn't say how long it is going at constant speed.
You could use v = vi + at to find the final velocity.
The average acceleration would be a = (change in velocity)/time
where "time" would be the total of the constant speed time and the 12 seconds of acceleration.
 
Whoops! Yeah, I forgot to specify that the 12 s was the entire period... the time when it was going 12 m/s was not included in calculations except as a starting value, i.e. v(0).

I'm sorry, I did ending up figuring this out. It was just averaging 12 m/s with the speed after 12 s with acceleration, which was 32.4 m/sec - 1.7 m/s^2 times 12 seconds and plus 12 m/s initial speed - to get 22.2 m/sec.

Oh, and I put average acceleration instead of average speed. Well. I'm sorry, I was not being nice to you. :(
 

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