Simple Normal/Tangential Acceleration Confirmation Needed

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SUMMARY

The discussion focuses on calculating the normal and tangential components of acceleration for a car rounding a bend with a radius of 200m and an initial velocity of 60 km/h, which is increasing at a rate of 5 m/s². The normal acceleration (an) is calculated as 1.38 m/s² using the formula an = v²/r. The tangential acceleration (at) is confirmed as 5 m/s². The resultant acceleration magnitude is determined to be 5.186 m/s², with a direction of 15.43 degrees from the horizontal. The final part of the problem, regarding the distance traveled before reaching a speed of 20 m/s, requires further exploration of uniformly accelerating motion equations.

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Griffy11
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Hi guys,

Got an exam this afternoon, and really need help with this. I think I'm right, but I just need verification and explanation.

Homework Statement



A car rounds a bend with a radius of 200m. At a particular instant, the car has a velocity of 60km/h. The speed of the car is increasing at a rate of 5m/s^2. Determine:

i) the normal and tangential components of the acceleration of the car
ii) the magnitude and direction of the resultant acceleration
iii) how far around the ben dthe car will travel before v=20m/s

Homework Equations


at = the rate at which v increases, given as 5m/s^2 in the question.
an = v^2/r

The Attempt at a Solution


My solutions:
i) an=v^2/r=((60/3.6)^2)/(200) = 1.38m/s^2
at = 5m/s^2

ii) |a| = sqrt(1.38^2+5^2) = 5.186m/s^2
theta = tan^-1(an/at) = tan^-1(1.38/5) = 15.43 degrees

iii) No idea. Really need help with this one.

Are i and ii correct? Help with iii appreciated also. Thank you so much.
 
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i) an=v^2/r=((60/3.6)^2)/(200) = 1.38m/s^2



For the final part think about the equations for uniformly accelerating bodies.
 

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