Average Acceleration and Time Taken to accelerate

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving a racing car's acceleration from 20 km/h to 160 km/h over a distance of 300 meters. Participants are examining the calculations related to average acceleration and time taken, while considering the effects of friction and wind resistance.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate average acceleration and time taken using provided equations but questions the correctness of their approach due to potential oversight of mass and forces.
  • Some participants question the sufficiency of information to determine average acceleration without assuming constant acceleration.
  • There is a suggestion to convert speeds from km/h to m/s to facilitate calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and addressing potential errors in the original equations. Guidance has been offered regarding unit conversion and the implications of assuming constant acceleration.

Contextual Notes

Participants note that the original equations may contain errors and that the problem requires careful consideration of the assumptions made regarding acceleration and forces involved.

AutumnBeds
Messages
22
Reaction score
0
Hi, I've been asked to solve below as part of an assignment. Below is pretty much what I've submitted but it has been concluded to be incorrect. I am unsure as to why hence the question. Is it due to the fact that I have not taken the mass or forces into consideration?

I have only taken these into consideration for questions (iii) and (iv) as shown below.

Any is greatly appreciated.

1. Homework Statement

A racing car of mass 850 kg accelerates from 20 km/h to 160 km/h over a distance of 300 metres. Frictional forces and wind resistance can be assumed to be 800N.

Determine the following:

(i)The average acceleration

(ii)The time taken to accelerate from 20 km/h to 160 km/h

(iii)The tractive force produced by the car to provide this acceleration - not required for this thread

(iv)The car finally reaches a speed of 250km/h. Friction and wind resistance are 1800 N at this speed. What power output is required to maintain this speed? - not required for this thread

Homework Equations



(i) v2=u22as

(ii) s= 1/2(u+v)t

The Attempt at a Solution


[/B]
1602=20SUP]2[/SUP]2a300

1602-202 / 2 * 300 = a

a=42 m/s2

(ii) 300= 1/2(160+20)t

t= 300/90

t= 3.3s
 
Last edited:
Physics news on Phys.org
AutumnBeds said:
Hi, I've been asked to solve below as part of an assignment. Below is pretty much what I've submitted but it has been concluded to be incorrect. I am unsure as to why hence the question. Is it due to the fact that I have not taken the mass or forces into consideration?

I have only taken these into consideration for questions (iii) and (iv) as shown below.

Any is greatly appreciated.

1. Homework Statement

A racing car of mass 850 kg accelerates from 20 km/h to 160 km/h over a distance of 300 metres. Frictional forces and wind resistance can be assumed to be 800N.

Determine the following:

(i)The average acceleration

(ii)The time taken to accelerate from 20 km/h to 160 km/h

(iii)The tractive force produced by the car to provide this acceleration - not required for this thread

(iv)The car finally reaches a speed of 250km/h. Friction and wind resistance are 1800 N at this speed. What power output is required to maintain this speed? - not required for this thread

Homework Equations



(i) v2=uSUP]2[/SUP]2as

(ii) s= 1/2(u+v)t

The Attempt at a Solution


[/B]
1602=20SUP]2[/SUP]2a300

1602-202 / 2 * 300 = a

a=42 m/s2

(ii) 300= 1/2(160+20)t

t= 300/90

t= 3.3s

You could first try solving the problem where the initial and final speeds are ##20m/s## and ##160 m/s## and see what answer you get.
 
AutumnBeds said:
The average acceleration
Second time today I have come across this blunder in a question.
There is not enough information to determine average acceleration. If you were told the acceleration is constant then you could find it from the two speeds and the distance, but if it is not then you need to know the time. For further discussion see section 3 of https://www.physicsforums.com/insights/frequently-made-errors-mechanics-forces/. (The discussion there is in respect of average force, but it apples equally to average acceleration.)
AutumnBeds said:
v2=uSUP]2[/SUP]2as
There is a mistake in that equation. I would have thought it just a typo, but you seem to have taken it to be correct.
 
PeroK said:
You could first try solving the problem where the initial and final speeds are ##20m/s## and ##160 m/s## and see what answer you get.
Thanks. I think this was the answer I was looking for. The comments on the work said Velocities require to be in m/s. Was a simple case of converting km/h to m/s.
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 18 ·
Replies
18
Views
4K
Replies
6
Views
2K
  • · Replies 13 ·
Replies
13
Views
21K
  • · Replies 16 ·
Replies
16
Views
11K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K