Simple Parallel-Plate Capacitor Question...please HeLP!!! 1. The problem statement, all variables and given/known data A parallel-plate capacitor is formed from two 2.32 cm × 2.32 cm electrodes spaced 2.85 mm apart. The electric field strength inside the capacitor is 85600000 N/C. What is the charge (in nC) on each electrode? 2. Relevant equations 3. The attempt at a solution E = Q / Eo * A A = 0.0232 * 0.0232 = 5.38e^-4 Q = (E * Eo * A) 8 1,000,000,000 = 407.75 nC What am I doing wrong?