1. The problem statement, all variables and given/known data A particle of mass 3.2kg is moving due west with a velocity of 6m/s. Another particle of mass 1.6kg is moving due north with a velocity of 5.0m/s. The two particles are interacting. After 2s the first particle is moving in the direction N 30° E with a velocity of 3m/s. Find the magnitude and direction of the second particle. 2. Relevant equations Δp1 = -Δp2 3. The attempt at a solution Okay, so I have all the information I need except that I need to decompose the direction of v1' (i.e. the velocity of the first particle after the interaction) into coordinates along the x and y axes. Here is my data: v1 = -6i v1' = 3(cos(60)i+sin(60)j) = 1.5i +2.6j v2 = 5j v2' = ? I write m1(v1' - v1) = -m2(v2' - v2) (i.e. Δp1 = -Δp2) Solving for v2' I get: (m1(v1 - v1')/m2) + v2 = v2' I put in the relevant data and get: -15i -0.2j = v2' But apparently this isn't correct. I keep checking my equation against the provided answer but I can't see where my mistake is even though I know my answer is wrong. I think I made a mistake when I decomposed the vector but I don't see how.