Simple Pendulum Period Calculation for Different Conditions

[mrnastytime]

Homework Statement

A pendulum has a period of 1.8 s.

Homework Equations

Its length is doubled. What is its period now?

The original pendulum is taken to a planet where g = 16 m/s2.
What is its period on that planet?

The Attempt at a Solution

T=2pi sqrt(L/g)
1.8=2pi sqrt(2L/g)



I don't what I am suppose to solve for. This looks like a very simple problem, but i can't seem to figure it out. Maybe I'm over thinking it.

 

[LowlyPion]

Homework Statement

A pendulum has a period of 1.8 s.

Homework Equations

Its length is doubled. What is its period now?

The original pendulum is taken to a planet where g = 16 m/s2.
What is its period on that planet?

The Attempt at a Solution

T=2pi sqrt(L/g)
1.8=2pi sqrt(2L/g)

I don't what I am suppose to solve for. This looks like a very simple problem, but i can't seem to figure it out. Maybe I'm over thinking it.

Well your equations are almost right, but they asked what happens to T when you double L. Presumably 1.8 s is what it is when l = L and they want to know what T is when l = 2L.

 

[mrnastytime]

What is I?...if the length is doubled, shouldn't the time increase? but how would i interpret that on paper with the given equation?

 

[LowlyPion]

What is I?...if the length is doubled, shouldn't the time increase? but how would i interpret that on paper with the given equation?

Not I, little L.

The variable l, in the equation you wrote

T = 2π (g/l)^1/2