Simple Pendulum Period Calculation for Different Conditions

Click For Summary

Homework Help Overview

The discussion revolves around the calculation of the period of a simple pendulum under different conditions, specifically when its length is doubled and when it is on a planet with a different gravitational acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the length of the pendulum and its period, questioning how to apply the formula T=2π√(L/g) when the length is doubled. There is uncertainty about what to solve for and how to interpret the changes in period mathematically.

Discussion Status

Some participants are exploring the implications of doubling the length on the period, while others are clarifying the variables used in the equations. There is a recognition that the original period of 1.8 seconds is based on a specific length, and the need to determine the new period when the length is modified is being examined.

Contextual Notes

Participants express confusion about the problem setup and the implications of changing the length and gravitational acceleration. There is an acknowledgment of the potential for overthinking the problem.

mrnastytime
Messages
28
Reaction score
0

Homework Statement


A pendulum has a period of 1.8 s.


Homework Equations


Its length is doubled. What is its period now?

The original pendulum is taken to a planet where g = 16 m/s2.
What is its period on that planet?



The Attempt at a Solution


T=2pi sqrt(L/g)
1.8=2pi sqrt(2L/g)



I don't what I am suppose to solve for. This looks like a very simple problem, but i can't seem to figure it out. Maybe I'm over thinking it.
 
Physics news on Phys.org
mrnastytime said:

Homework Statement


A pendulum has a period of 1.8 s.

Homework Equations


Its length is doubled. What is its period now?

The original pendulum is taken to a planet where g = 16 m/s2.
What is its period on that planet?

The Attempt at a Solution


T=2pi sqrt(L/g)
1.8=2pi sqrt(2L/g)

I don't what I am suppose to solve for. This looks like a very simple problem, but i can't seem to figure it out. Maybe I'm over thinking it.

Well your equations are almost right, but they asked what happens to T when you double L. Presumably 1.8 s is what it is when l = L and they want to know what T is when l = 2L.
 
What is I?...if the length is doubled, shouldn't the time increase? but how would i interpret that on paper with the given equation?
 
mrnastytime said:
What is I?...if the length is doubled, shouldn't the time increase? but how would i interpret that on paper with the given equation?

Not I, little L.

The variable l, in the equation you wrote

T = 2π (g/l)1/2
 

Similar threads

Replies
17
Views
1K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 27 ·
Replies
27
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K