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## Homework Statement

A rock dropped from a cliff covers one-third of its total distance to the ground in the last second of its fall. Air resistance is negligible. How high is the cliff?

## Homework Equations

v = v

^{0}+ at

^{2}

h = v

_{0}t + 0.5at

^{2}

v

^{2}= v

_{0}

^{2}+ 2ah

h = distance in this case

## The Attempt at a Solution

t for [itex]\frac{h}{3}[/itex] = 1 sec

[itex]\frac{h}{3}[/itex] = v

_{0}(1) + 0.5(-9.81)(1

^{2})

.

.

.

h = 3v

_{o}+ 14.715[itex]\frac{m}{sec^{2}}[/itex]

I've re-arranged the equations but I'm always left with 2 unknowns. I understand this is basic stuff, so just a bump in the right direction will be much appreciated.

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