Simple Projectile Motion of ball

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RedBurns
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Can someone tell me what I'm doing wrong here:

A ball is thrown horizontally from the roof of a building 58 m tall and lands 35 m from the base. What was the ball's initial speed?

X0= 0m Y0= 0m
X= 58 m Y= 35 m
Vx=? Vy=0 m/s
Ax=0 m/s/s Ax=-9.8 m/s/s
T=?

35=0+0T-.5(-9.8)T^2
T=2.6 s

58=0+Vx(2.6)
Vx= 22 m/s <----------I know this is wrong
 
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RedBurns said:
Can someone tell me what I'm doing wrong here:

A ball is thrown horizontally from the roof of a building 58 m tall and lands 35 m from the base. What was the ball's initial speed?

X0= 0m Y0= 0m
X= 58 m Y= 35 m
Vx=? Vy=0 m/s
Ax=0 m/s/s Ax=-9.8 m/s/s
T=?

35=0+0T-.5(-9.8)T^2
T=2.6 s

58=0+Vx(2.6)
Vx= 22 m/s <----------I know this is wrong

You've got your distances reversed! The building is 58m tall- that's the vertical distance: Y= 58m. The ball went 35 m horizontally: X= 35m
 
Thanks! I should have known it was something like that after cheking my math so any times