A 9.00 kg hanging weight is connected by a string over a light pulley to a 5.00 kg block that is sliding on a flat table (Fig. P5.8). If the coefficient of kinetic friction is 0.560, find the tension in the string.(adsbygoogle = window.adsbygoogle || []).push({});

f_{k}= µ_{k}N, F = ma, N_{2}= m_{2}g, 5.00 kg mass = m_{2}, 9.00 kg mass = m_{1}

N = (5)(9.8) = 49

sigma f = ma

T + m_{2}g - f_{k}= (m_{1}+ m_{2})a

T + (9)(9.8) - (µ_{k})(N) = (14)a

T + (9)(9.8) - (.560)(49) = (14)a

I'm lost at this point. Thanks in advance.

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# Homework Help: Simple pulley system + kinetic friction, find tension

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