Is the Energy Change in a Bohr Atom Always Equal to One Photon?

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SUMMARY

The energy change in a Bohr atom during an electron's transition from a higher-energy shell to a lower-energy shell is equal to the energy of one photon, represented by the equation ΔE = hf. This relationship confirms that a downward transition typically results in the emission of a single photon. While it is possible for multiple photons to be involved in different scenarios, the standard case adheres to this one-to-one correspondence between energy change and photon emission.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with the Bohr model of the atom
  • Knowledge of photon energy calculations using the formula E = hf
  • Basic grasp of electron energy levels and transitions
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  • Research the Bohr model of the hydrogen atom in detail
  • Explore the concept of photon emission and absorption in quantum mechanics
  • Learn about energy level transitions in other atomic models, such as the quantum mechanical model
  • Investigate the implications of multi-photon processes in atomic transitions
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Students of physics, educators teaching quantum mechanics, and researchers interested in atomic energy transitions will benefit from this discussion.

Vishera
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From Wikipedia, the following diagram explains the energy emitted when an electron jumps from a higher-energy shell to a lower-energy shell:
500px-Bohr-atom-PAR.svg.png


I already know that the energy of a single photon is equal to ##hf## and in this diagram, ##\Delta E=hf##. Does that mean that ##\Delta E## is only one photon?
 
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Yes, a "downward" transition between two energy levels produces a single photon.
 
jtbell said:
Yes, a "downward" transition between two energy levels produces a single photon.
It does not have to, but this is the typical case, yes.
 

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