Simple Strategies for Solving Problems to Effective Solutions

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Homework Help Overview

The discussion revolves around solving a triple integral in spherical coordinates, specifically related to volume calculations. Participants are exploring the setup and limits of integration, as well as the implications of the integrand's structure.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the integration process, with some suggesting direct integration of variables and others questioning the appropriateness of the integration limits. There are attempts to clarify the setup of the problem and the implications of the chosen limits.

Discussion Status

The discussion is active, with various interpretations of the integration limits being explored. Some participants have provided insights into the integration process, while others have raised concerns about specific aspects of the problem setup, particularly regarding the limits of integration.

Contextual Notes

There are mentions of potential issues with the limits of integration, particularly for the angle variable in spherical coordinates, which some participants find unusual. The original poster's problem context is not fully detailed, leading to some ambiguity in the discussion.

Superposed_Cat
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How would you go about solving this?
 

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Integrate it?
Where is your specific problem?
 
It's a triple integral (a volume, for example). You need two more sets of integration limits. Since one of the integration variables doesn't appear in the integrand you can integrate it directly - it would most likely end up as a factor of 2pi. Looking at the remaining parts, you can integrate each separately, taking into account the integration limits.
 
c∫d α∫β 1∫2 ρ^2 sin∅ dρd∅dθ

= c∫d α∫β [(ρ^3)/3 sin∅] [1,2] d∅dθ
= c∫d α∫β 7/3 sin∅ d∅dθ
= c∫d [-7/3 cos∅] [α,β] dθ
= c∫d [-7/3 cosβ] - [-7/3 cosα] dθ
= c∫d 7/3 (cosα - cosβ) dθ
= [(7θ)/3 (cosα - cosβ)] [c,d]
= [(7d)/3 (cosα - cosβ)] - [(7c)/3 (cosα - cosβ)]
= (1/3)(7d-7c)(cosα - cosβ)

This is the general solution where α≤∅≤β and c≤∅≤d
 
Sorry, cropped too much there.
 

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That's easy then! Since the limits of integration are all constants and the integrand is just a product of functions of the separate variables, that is just
\left(\int_1^2 \rho^2 d\rho\right)\left(\int_{\pi/2}^\pi \sin(\phi) d\phi\right)\left(\int_0^2 d\theta\right)

Though I must say the limits of integration on that last, d\phi, integral look suspicious to me! It's not impossble- but "0 to 2 radians" seems peculiar. "0 to 2\pi" would see much more reasonable. That would be integrating over a hemi-spherical "cup", below the xy-plane with thickness from 1 to 2.
 
Why is that weird?
 
TysonM8 said:
c∫d α∫β 1∫2 ρ^2 sin∅ dρd∅dθ

= c∫d α∫β [(ρ^3)/3 sin∅] [1,2] d∅dθ
= c∫d α∫β 7/3 sin∅ d∅dθ
= c∫d [-7/3 cos∅] [α,β] dθ
= c∫d [-7/3 cosβ] - [-7/3 cosα] dθ
= c∫d 7/3 (cosα - cosβ) dθ
= [(7θ)/3 (cosα - cosβ)] [c,d]
= [(7d)/3 (cosα - cosβ)] - [(7c)/3 (cosα - cosβ)]
= (1/3)(7d-7c)(cosα - cosβ)

This is the general solution where α≤∅≤β and c≤∅≤d

Dude, you should seriously learn latex! It's not that hard and it makes it so much easier for everyone to read what you write. It also looks way better and it's probably better for you as well!

Just take a look at this link.
 
Superposed_Cat said:
Why is that weird?

You're integrating using spherical coordinates. ##\theta## is an angle and it seems weird that it goes from ##0## to ##2## radians.
 

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