Simple three charges problem in 1D

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SUMMARY

The discussion revolves around calculating the net force on a third charge, q3=-2x10^-9 C, positioned at x=0 due to two other charges, q1=3x10^-9 C at x=0.4m and q2=5x10^-9 C at x=-0.2m. Using Coulomb's Law, the forces calculated were F(13)=3.375x10^6 N directed towards the +x axis and F(23)=2.247x10^6 N directed towards the -x axis, resulting in a net force of 1.128x10^6 N in the +x direction. However, discrepancies arose in the exponent of the calculated force, indicating a potential error in the calculations.

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Homework Statement


Two charges are on the X axis as follows: q1=3x10^-9 C at x=0.4metre and q2=5x10^-9 C at x=-0.2m. What is the size and direction of the sum of forces are on third charge q3=-2x10^-9 C at x=0?

Homework Equations


F=k|q1q2|/r^2

The Attempt at a Solution


By my calculation I achieved F(13)=3.375x10^6 N in the +x direction, and F(23)=2.247x10^6 N in the -x direction, and the sum of forces is 1.128x10^6 N to the +x direction. But the book says otherwise...
 
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Something is a bit off, when I compute F(13) I get a very different exponent for the force. 3.37*10^(-7) N.
 
oh, darn
 

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