1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple wave questions- am I right?

  1. Sep 4, 2008 #1
    1. The problem statement, all variables and given/known data
    Consider the sum of two waves , y1(x,t) + y2(x,t) where y1(x,t) is the wave described by y1(x,t) = Asin(kx-[tex]\omega[/tex]t) and y2 is a wave of the same amplitude moving in the opposite direction. These waves have been chosen so that their sum can be written as follows: Ys= Ye(x)*Yt(t).

    This form is significant because Ye , called the envelope, depends only on position, and Yt depends only on time. Traditionally, the time function is taken to be a trigonometric function with unit amplitude; that is, the overall amplitude of the wave is written as part of Ye.

    1) At the position x=0 what is the string's displacement (assuming the standing wave Ys is present) ? Express your answer in terms of the parameters given in the problem introduction.

    2) At some times, the string will be perfectly straight. Find the first time t1 when this is true. Express t1 in terms of [tex]\omega[/tex], k, and necessary constants.




    2. Relevant equations



    3. The attempt at a solution

    1) So for wave 1 the displacement eqn. is y1= Asin(kx-[tex]\omega[/tex]t) & for wave 2 it is y2=Asin(kx+[tex]\omega[/tex]t). When I add them together, I get:
    Ys= Asin(kx-[tex]\omega[/tex]t) + Asin(kx+[tex]\omega[/tex]t)

    and using a trig identity,
    I get Ys= 2Asin(kx)*cos([tex]\omega[/tex]t)

    so my question is: For part 1 do I just plug in x=0 to the x dependent part of the eqn? If so I get the displacement is 0.

    For part 2 I set up this equation using the time dependent part of the equation:

    0=cos[tex]\omega[/tex]t [tex]\pi[/tex]/2 = [tex]\omega[/tex]t and I got t1= [tex]\pi[/tex]/(2[tex]\omega[/tex])

    Am I interpreting the equation correctly?

    Thanks
     
    Last edited: Sep 4, 2008
  2. jcsd
  3. Sep 4, 2008 #2

    Hootenanny

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Looks good to me.
    Again, looks good to me.
     
  4. Sep 4, 2008 #3

    Redbelly98

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper

    There is another function that also fits the condition "y2 is a wave of the same amplitude moving in the opposite direction".

    Is there any more information that you have perhaps omitted?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?