Simplify Homework: Solving for i in a Complex Equation

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Homework Help Overview

The problem involves solving for the variable i in a complex equation related to financial mathematics, specifically dealing with interest rates and compounding. The equation includes terms that suggest it may involve exponential growth or decay.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants suggest various methods for simplifying the equation, including writing (1+i) in polar form and substituting a = (1+i)^22 to make the problem more manageable. Some express confusion about the original poster's approach and the implications of the variable i.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations and methods for approaching the problem. Some guidance has been offered, but there is no clear consensus on the best path forward.

Contextual Notes

There is a need for clarification on whether i represents the imaginary unit or an interest rate, which may affect the approach to solving the equation. Additionally, some participants note the potential necessity of numerical or graphical methods for finding a solution.

cs23
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Homework Statement



solve for i

4100=100{[(1+i)^22 - 1]/i(1+i)^22} + 5000[1/(1+i)^22]



Homework Equations





The Attempt at a Solution



4100=100{/ i} + 5000[1/(1+i)^22]
4100= 100+5000[1/i + 1/(1+i)^22]
4100=5100[1/(1+ i)^23]
0.803=[1/(1+ i)^23]
(1+ i)^23= 1/0.803=1.24

i= 23 sqrt(1.24) -1
 
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hi cs23! :smile:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)

sorry, not following that :confused:

write 1+i in polar form (re), then you can immediately find (1+i)22 and 1/(1+i) :smile:
 
Another trick is to substitute a = (1+i)^22. Solve for a. After that, finding i will become much easier.
 
In LaTeX that's: [tex]4100=100\frac{(1+i)^{22} - 1}{i(1+i)^{22}}+5000\frac{1}{(1+i)^{22}}[/tex]

Following gb7nash's suggestion this becomes: [tex]4100=100\frac{a - 1}{i\cdot a}+5000\frac{1}{a}[/tex]
 
SammyS said:
In LaTeX that's: [tex]4100=100\frac{(1+i)^{22} - 1}{i(1+i)^{22}}+5000\frac{1}{(1+i)^{22}}[/tex]

Following gb7nash's suggestion this becomes: [tex]4100=100\frac{a - 1}{i\cdot a}+5000\frac{1}{a}[/tex]

Ah, I didn't notice that one i. My method won't work. :frown:
 
gb7nash said:
Ah, I didn't notice that one i. My method won't work. :frown:
Well, it will make simplifying a little easier.... maybe not much.
 
It probably needs to be done graphically or numerically.
 
For clarification, you should state whether i = sqrt (-1) or if i represents an interest rate in some type of compounding interest problem.
 

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