Simplify Radical sqrt(65/7)/[2sqrt(2)] | Step-by-Step Guide & Explanation

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
5 replies · 3K views
js14
Messages
43
Reaction score
0
sqrt(65/7)/[2sqrt(2)] I know how to simplfy radicals but this one has me stuck. I tried to answer it and i got sqrt(65)/[2*sqrt(2)] is this right?
 
Physics news on Phys.org
js14 said:
sqrt(65/7)/[2sqrt(2)] I know how to simplfy radicals but this one has me stuck. I tried to answer it and i got sqrt(65)/[2*sqrt(2)] is this right?
No.

You lost sqrt(7) somehow.

This is the same as
[tex]\frac{\sqrt{65}}{\sqrt{7}} \cdot \frac{1}{2\sqrt{2}}[/tex]

Multiply by 1 in the form of sqrt(14)/sqrt(14) to rationalize the denominator.
 
Ok I get 1/2 * sqrt(65/14). is this right?
 
yes, that is correct.

you can also simplify this by doing the following

[tex] \frac{\sqrt{65}}{\sqrt{7}} \cdot \frac{1}{2\sqrt{2}} = \frac{1}{2} \frac{\sqrt{65}}{\sqrt{7} \sqrt{2}} = \frac{1}{2} \frac{\sqrt{65}}{\sqrt{7 \cdot 2}} = \frac{1}{2} \sqrt{\frac{65}{14}}[/tex]
 
Often the textbook's answer will appear without radicals in the denominator. If that's the case in your textbook, multiply the answer that ojs gave by sqrt(14)/sqrt(14), which gives
[tex]\frac{\sqrt{910}}{28}[/tex]