Simplify Radical sqrt(65/7)/[2sqrt(2)] | Step-by-Step Guide & Explanation

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Homework Help Overview

The discussion revolves around simplifying the expression sqrt(65/7)/[2sqrt(2)], which involves radical expressions and rationalizing denominators.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore different simplification methods for the radical expression, questioning the accuracy of initial attempts and discussing the process of rationalizing the denominator.

Discussion Status

Some participants have provided guidance on how to approach the simplification, while others have confirmed the correctness of certain steps. Multiple interpretations of the simplification process are being explored.

Contextual Notes

There is an emphasis on ensuring that radicals do not remain in the denominator, reflecting common textbook conventions. Participants also note potential errors in earlier simplifications.

js14
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sqrt(65/7)/[2sqrt(2)] I know how to simplfy radicals but this one has me stuck. I tried to answer it and i got sqrt(65)/[2*sqrt(2)] is this right?
 
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js14 said:
sqrt(65/7)/[2sqrt(2)] I know how to simplfy radicals but this one has me stuck. I tried to answer it and i got sqrt(65)/[2*sqrt(2)] is this right?
No.

You lost sqrt(7) somehow.

This is the same as
\frac{\sqrt{65}}{\sqrt{7}} \cdot \frac{1}{2\sqrt{2}}

Multiply by 1 in the form of sqrt(14)/sqrt(14) to rationalize the denominator.
 
Ok I get 1/2 * sqrt(65/14). is this right?
 
yes, that is correct.

you can also simplify this by doing the following

<br /> \frac{\sqrt{65}}{\sqrt{7}} \cdot \frac{1}{2\sqrt{2}} = \frac{1}{2} \frac{\sqrt{65}}{\sqrt{7} \sqrt{2}} = \frac{1}{2} \frac{\sqrt{65}}{\sqrt{7 \cdot 2}} = \frac{1}{2} \sqrt{\frac{65}{14}}<br />
 
Often the textbook's answer will appear without radicals in the denominator. If that's the case in your textbook, multiply the answer that ojs gave by sqrt(14)/sqrt(14), which gives
\frac{\sqrt{910}}{28}
 
Thanks!
 

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