Simplifying √(3+2√(2)): Find the Integer and Irrational

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Homework Help Overview

The discussion revolves around simplifying the expression √(3 + 2√(2)), with the goal of identifying an integer and an irrational number within the simplification process.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the validity of breaking down the expression under the square root, with some questioning the legality of certain simplification steps. There are discussions about the implications of manipulating square roots and the assumptions behind those manipulations.

Discussion Status

The conversation includes hints and clarifications regarding the simplification process, with participants expressing differing views on the legality of certain mathematical operations. There is no explicit consensus, but the dialogue appears to be productive in exploring the topic.

Contextual Notes

Some participants express concerns about the assumptions made in the simplification process and the potential for misunderstanding mathematical principles related to square roots.

chillfactor
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Homework Statement



√(3+2√(2)) can be simplified into a fairly simple sum of two number: one is an integer and one is an irrational number . Find them and show you are correct by squaring both sides of the "equation"

Homework Equations





The Attempt at a Solution

 
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Here's a hint: note that
[tex]\sqrt{3 + 2\sqrt{2}} = \sqrt{1 + 2\sqrt{2} + 2}[/tex]
 
isnt that illegal. By the same logic I could simplify the square root of nine to the square root of 9 ones and solve and get nine
 
the whole thing is under the square root .. it won't result to 9.
 
Isn't what illegal? All he did was say that 3=2+1. he didn't break up the square root
 
Writing [itex]\sqrt{9}= \sqrt{1+ 1+ 1+ 1 +1 + 1+ 1+ 1+ 1}[/itex] is perfectly legal.

It is thinking that that last is the sum of
[tex]\sqrt{1}+ \sqrt{1}+ \sqrt{1}+ \sqrt{1}+ \sqrt{1}+ \sqrt{1}+ \sqrt{1}+ \sqrt{1}+ \sqrt{1}[/tex]

that is illegal.
 
Last edited by a moderator:
Sorry. I have removed the "answer" to the problem.
 

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