Simplifying a Boolean logic function with LUT terms

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keroppi
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Hi I am trying to solve a LUT question.

x2 x3' x6 + x2 x3 x4' x5 + x3' + x1 x2 x3 x4 x5 + x1' x4...

im having a real hard time simplfying this function however. What i have tried doing is factoring out the x3' factor to reduce one of the terms, however, the rest, I am not sure how to simplify. thanks for the help!
 
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