MHB Simplifying compound fractions

Click For Summary
To simplify the compound fraction [1/(1+x+h) - 1/(1+x)] / h, finding a common denominator for the top two fractions is essential. The common denominator is (1+x+h)(1+x), allowing for the expression to be rewritten as [(1+x) - (1+x+h)] / [(1+x+h)(1+x)]. This results in a simplified numerator of -h, leading to the overall simplification of the compound fraction. The final expression can be further reduced by dividing by h, yielding -1/[(1+x+h)(1+x)]. Understanding how to manipulate common denominators is crucial in simplifying such fractions effectively.
datafiend
Messages
31
Reaction score
0
Hi all,
I'm having a problem simplifying this:

[1/(1+x+h) - 1/(1+x)] / h

How do you get the common denominators for the top 2 fractions?

Thanks
 
Mathematics news on Phys.org
Maybe try to find a common denominator for 1+x+h and 1+x.

$(1+x+h)\times(1+h) = x^2+x(2+h)+1+h$
 
Last edited:
In the numerator, I would use:

$$\frac{1}{a}-\frac{1}{b}=\frac{b-a}{ab}$$
 
mark,
thanks again!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K