Simplifying Exterior Angles in a Polygon

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Frank212
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Homework Statement


bandicam 2016-08-14 00-45-30-451.jpg


Homework Equations


sum interior angles (n-2)*180
angles of a quadrilateral: a+b+c=d = 360
[/B]

The Attempt at a Solution


What do you do with the exterior angle?
80+130+a+x=360
 
on Phys.org
Frank212 said:

Homework Statement


View attachment 104635

Homework Equations


sum interior angles (n-2)*180
angles of a quadrilateral: a+b+c=d = 360
[/B]

The Attempt at a Solution


What do you do with the exterior angle?
105+80+130+a+x=360

How would you find ##x## from the information in the diagram?
 
Ray Vickson said:
How would you find ##x## from the information in the diagram?
a+130+x=360
180-100=80
x=80
130+80+85= 295
360-295=65
a=65
 
Frank212 said:
a+130+x=360
180-100=80
x=80
130+80+85= 295
360-295=65
a=65

Much easier: just use the fact that 100+x = 180, because the angles 100 and x make up a straight line. (I know you got the correct value for x above, but I found your argument to be confusing and not as step-by-logical-step as it should be.)