Simplifying Factorials: How to Simplify the Expression (2n-1)! / (2n+1)!

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SUMMARY

The expression $$ \frac{(2n-1)!}{(2n+1)!} $$ simplifies to $$ \frac{1}{(2n)(2n+1)} $$ through the cancellation of factorial terms. By expanding the factorials, it becomes clear that the numerator consists of the product of all integers from 1 to (2n-1), while the denominator includes the product of integers from 1 to (2n+1). This simplification process highlights the importance of understanding factorial notation and its properties.

PREREQUISITES
  • Understanding of factorial notation and operations
  • Basic algebraic manipulation skills
  • Familiarity with mathematical expressions involving variables
  • Knowledge of sequences and series
NEXT STEPS
  • Study the properties of factorials in combinatorics
  • Explore simplification techniques for rational expressions
  • Learn about sequences, particularly odd and even integer sequences
  • Investigate the applications of factorials in probability and statistics
USEFUL FOR

Students studying mathematics, particularly those focusing on algebra and combinatorics, as well as educators looking for effective methods to teach factorial simplifications.

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Homework Statement



$$ \frac{(2n-1)!}{(2n+1)!} $$

How do you simplify this factorial?
 
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Just write out the factorials. Then you'll see immediately how to simplify the expression.
 
vanhees71 said:
Just write out the factorials. Then you'll see immediately how to simplify the expression.

I cannot tell from writing them out.
$$\frac{1*3*5*7*9...(2n-1)!}{3*5*7*9*11...(2n+1)!} $$
Please explain.Edit:
Nvm, I understand. Thank you!

$$\frac{(2n-1)!}{(2n+1)!} = \frac{(2n-1)*(2n-2)*(2n-3)*(2n-4)...2*1}{(2n+1)*(2n)*(2n-1)*(2n-2)...2*1} $$
$$ = \frac{1}{(2n)*(2n+1)} $$

or

$$\frac{(2n-1)!}{(2n+1)!} = \frac{(2n-1)!}{(2n+1)*(2n)*(2n-1)!} $$
$$ = \frac{1}{(2n+1)*(2n)} $$
 
Last edited:

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