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Homework Help: Simplifying Radicals with varibles?

  1. Nov 27, 2008 #1
    I understand that the square root of (for example)j^16 is j^8. But when you have an odd squared root, like the square root of j^19, would it be j^9square root of j?

    Another quick question 12 radical 36 would be 72?

    Sorry, I know this is basic algebra, but I really have forgotten how to do it...
     
  2. jcsd
  3. Nov 28, 2008 #2

    Mentallic

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    Delete - Multipost.
     
  4. Nov 28, 2008 #3

    Mentallic

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    Yes that is exactly what it would be.

    [tex]\sqrt{x}=x^{\frac{1}{2}}[/tex]
    and
    [tex]\sqrt{x^a}=x^{\frac{a}{2}[/tex]

    So for your question [tex]\sqrt{j^{16}}=j^{\frac{16}{2}}=j^8[/tex]

    Thus, [tex]\sqrt{j^19}=j^{\frac{19}{2}}=j^{9\frac{1}{2}}=j^9\sqrt{j}[/tex]


    For the second one, [tex]12\sqrt{36}=72[/tex] because [tex]\sqrt{36}=6[/tex] therefore [tex]12x6=72[/tex]

    If theres something you still don't understand, just ask :smile:
     
  5. Nov 28, 2008 #4
    I would add a plus or minus to every result :tongue:
     
  6. Nov 28, 2008 #5

    Mentallic

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    Well if you want to be wrong then go ahead.
     
    Last edited: Nov 28, 2008
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