Simplifying tan(2arccotx) - Peter's Question at Yahoo Answers

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SUMMARY

The discussion focuses on simplifying the expression tan(2arccot(x)). The simplification process utilizes the double-angle identity for tangent, resulting in the expression y = 2tan(cot^{-1}(x)) / (1 - tan^2(cot^{-1}(x))). By applying the identity cot^{-1}(x) = tan^{-1}(1/x), the expression is further simplified to y = 2/x / (1 - (1/x)^2). Ultimately, the final simplified form is y = 2x / (x^2 - 1).

PREREQUISITES
  • Understanding of trigonometric identities, specifically the double-angle identity for tangent.
  • Familiarity with inverse trigonometric functions, particularly cotangent and tangent.
  • Basic algebraic manipulation skills, including simplification of fractions.
  • Knowledge of the relationship between cotangent and tangent functions.
NEXT STEPS
  • Study the derivation and applications of the double-angle identities in trigonometry.
  • Explore the properties and graphs of inverse trigonometric functions.
  • Practice simplifying complex trigonometric expressions using various identities.
  • Learn about the applications of trigonometric identities in calculus, particularly in integration and differentiation.
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Students and educators in mathematics, particularly those studying trigonometry and calculus, as well as anyone looking to enhance their skills in simplifying trigonometric expressions.

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Here is the question:

How to simplify tan(2arccot x)?

How do you to simplify tan(2arccotx) as much as possible?

(using trigonometric identities)

thank you!

I have posted a link there to this thread so the OP can view my work.
 
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Hello Peter,

We are given to simplify:

$$y=\tan\left(2\cot^{-1}(x) \right)$$

Let's first apply the double-angle identity for the tangent function, which is:

$$\tan(2\theta)=\frac{2\tan(\theta)}{1-\tan^2(\theta)}$$

and we obtain:

$$y=\frac{2\tan\left(\cot^{-1}(x) \right)}{1-\tan^2\left(\cot^{-1}(x) \right)}$$

Next, we may apply the identity:

$$\cot^{-1}(x)=\tan^{-1}\left(\frac{1}{x} \right)$$

and we obtain:

$$y=\frac{2\tan\left(\tan^{-1}\left(\frac{1}{x} \right) \right)}{1-\tan^2\left(\tan^{-1}\left(\frac{1}{x} \right) \right)}$$

This reduces to:

$$y=\frac{\dfrac{2}{x}}{1-\left(\dfrac{1}{x} \right)^2}$$

Multiplying the right side by $$1=\frac{x^2}{x^2}$$ we get:

$$y=\frac{2x}{x^2-1}$$
 

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