TKDKicker89 Messages 2 Reaction score 0 Thread starter Jul 7, 2005 #1 Can anyone help asap? tan(arccos x/3) THanks
Jameson Insights Author Gold Member MHB Messages 4,533 Reaction score 13 Jul 7, 2005 #2 Draw a right triangle. If arccos x/3 = theta, draw that triangle.
BobG Science Advisor Messages 364 Reaction score 87 Jul 7, 2005 #3 if [tex]\theta=cos^{-1} \frac{x}{3}[/tex] then [tex]\frac{x}{3}[/tex] is the cosine of [tex]\theta[/tex] You can use the pythagorean theorem to find the sine of [tex]\theta[/tex] [tex]\cos^2 \theta + \sin^2 \theta = 1[/tex] The tangent of [tex]\theta[/tex] is [tex]\frac{sin \theta}{cos \theta}[/tex]
if [tex]\theta=cos^{-1} \frac{x}{3}[/tex] then [tex]\frac{x}{3}[/tex] is the cosine of [tex]\theta[/tex] You can use the pythagorean theorem to find the sine of [tex]\theta[/tex] [tex]\cos^2 \theta + \sin^2 \theta = 1[/tex] The tangent of [tex]\theta[/tex] is [tex]\frac{sin \theta}{cos \theta}[/tex]