(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

tan[arctan(2/3)+arccos(8/17)]

2. Relevant equations

tan(u+v)=[itex]\frac{\tan u+\tan v}{1-\tan u\tan v}[/itex]

3. The attempt at a solution

After drawing 2 triangles for arctan and arccos (both in Quadrant 1), and inserting them into the addition formula for tan, I get:

[tex]\frac{\frac{2}{3}+\frac{15}{8}}{1-\frac{2}{3}(\frac{15}{8})}[/tex]

is that right?

if so, then maybe my math is off...

I got the numerator reduced to 23/8

and denominator of -1/4

for a total of -23/3 ...but thats not correct.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Tan[arctan(2/3) + arccos(8/17)]

**Physics Forums | Science Articles, Homework Help, Discussion**