(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

tan[arctan(2/3)+arccos(8/17)]

2. Relevant equations

tan(u+v)=[itex]\frac{\tan u+\tan v}{1-\tan u\tan v}[/itex]

3. The attempt at a solution

After drawing 2 triangles for arctan and arccos (both in Quadrant 1), and inserting them into the addition formula for tan, I get:

[tex]\frac{\frac{2}{3}+\frac{15}{8}}{1-\frac{2}{3}(\frac{15}{8})}[/tex]

is that right?

if so, then maybe my math is off...

I got the numerator reduced to 23/8

and denominator of -1/4

for a total of -23/3 ...but thats not correct.

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# Tan[arctan(2/3) + arccos(8/17)]

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