- #1
jrjack
- 111
- 0
Homework Statement
tan[arctan(2/3)+arccos(8/17)]
Homework Equations
tan(u+v)=[itex]\frac{\tan u+\tan v}{1-\tan u\tan v}[/itex]
The Attempt at a Solution
After drawing 2 triangles for arctan and arccos (both in Quadrant 1), and inserting them into the addition formula for tan, I get:
[tex]\frac{\frac{2}{3}+\frac{15}{8}}{1-\frac{2}{3}(\frac{15}{8})}[/tex]
is that right?
if so, then maybe my math is off...
I got the numerator reduced to 23/8
and denominator of -1/4
for a total of -23/3 ...but that's not correct.