Yeah, you've got it.
Remember that raising a power of ##x## to a power is like multiplying the exponents. So, ##(x^n)^m = x^{nm}##. In the numerator, you've got ##2x^{15}##, while in the denominator, you've got ##4x^2##. The 4 cancels the 2, and by basic exponent laws, the square in the denominator cancels two powers of ##x## in the numerator. So, you get ##\frac{1}{2} x^{13}##, which is what you got.