Simultaneously unitarily diagonalizeable matrices commute

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Matrices A and B are simultaneously unitarily diagonalizable, implying the existence of a unitary matrix P such that P^{-1}AP = D_{1} and P^{-1}BP = D_{2}, where D_{1} and D_{2} are diagonal matrices. Since diagonal matrices commute, it follows that D_{1}D_{2} = D_{2}D_{1}. The discussion highlights the necessity of proving that A and B are normal to utilize the unitary property effectively. A user seeks clarification on whether their current proof is sufficient to demonstrate that AB = BA. The conversation emphasizes the connection between simultaneous diagonalizability and the commutativity of matrices.
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Homework Statement


Matrices A and B are simultaneously unitarily diagonalizeable. Prove that they commute.

Homework Equations


As A and B are simultaneously unitarily diagonalizeable, there exists a unitary matrix P such that

P^{-1}AP = D_{1} and P^{-1}BP = D_{2}, where D_{1} and D_{2} are diagonal matrices., where D_{1} and D_{2} are diagonal matrices.

Diagonal matrices always commute.

A unitary matrix multiplied by its conjugate transpose results in an identity matrix.

The Attempt at a Solution



So far I have that
P^{-1}APP^{-1}BP = P^{-1}ABP = D_{1}D_{2} and
P^{-1}BPP^{-1}AP = P^{-1}BAP = D_{2}D_{1}
D_{1}D_{2} = D_{2}D_{1} P^{-1}ABP = P^{-1}BAP.

Is this enough to show that AB = BA? Where would I use the fact that P is unitary?

Also, how do I delete the latex part at the top? It goes straight to the first latex entry. I put empty tex tags at the top to make it as non-distracting as possible, but if I don't add them, the gibberish goes straight to the next latex section.
 
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Bump?
 
you don't need the unitary part, since two diagonalizable matrices are generally simutaneously diagonalizable if and only if they commute; the unitary part is needed if you also assert that the matrices are both normal -- did you leave that out?
 
I didn't, but I just recieven an update to the assignment that says I need to show the matrices are normal.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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