The problem involves calculating the width of the central maximum produced by a 0.42 mm-diameter slit illuminated by light with a wavelength of 510 nm, observed on a screen 1.8 m away. The correct formula to use is f = λx/s, where λ is the wavelength, x is the distance to the screen, and s is the slit width. The user initially provided incorrect answers of 4.4 mm and 2.2 mm, which were identified as incorrect due to the misuse of the formula. The correct approach requires a proper understanding of single-slit diffraction principles.
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Please show how you got those answers. It is hard to guess what you did wrong otherwise.Plasmosis1 said:I tried two answers, 4.4mm and 2.2mm and they are both wrong. Any suggestions?
Plasmosis1 said:Homework Statement
A 0.42 -mm-diameter hole is illuminated by light of wavelength 510nm. What is the width (in mm) of the central maximum on a screen 1.8m behind the slit?
Homework Equations
f=λx/s
The Attempt at a Solution
I tried two answers, 4.4mm and 2.2mm and they are both wrong. Any suggestions?