What is the missing variable in the double slit interference pattern?

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SUMMARY

The discussion focuses on calculating the slit width and the distance between the centers of two slits in a double slit interference pattern created by laser light with a wavelength of 517 nm. The interference pattern shows bright bands that are 1.15 cm apart, with the third bright bands on either side of the central maximum missing. The relevant equation used is dsinθ = mλ, where d represents the distance between the slits, and λ is the wavelength. The correct value for d was calculated as 3.93x10-5 m, which is essential for determining the slit width.

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  • Knowledge of trigonometry for angle calculations
  • Basic grasp of diffraction and its relation to slit width
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  • Learn about the conditions for missing bright bands in interference patterns
  • Explore the relationship between slit width and diffraction effects
  • Investigate experimental setups for measuring interference patterns
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CricK0es
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Homework Statement


Laser light of wavelength 517 nm illuminates two identical slits, producing an interference pattern on a screen 87.5 cm from the slits. The bright bands are 1.15 cm apart, and the third bright bands on either side of the central maximum are missing in the pattern.

a.) Find the slit width, a
b.) Find the distance between their centres, d

Homework Equations



dsinθ = mλ

The Attempt at a Solution



I'm fairly sure I can do b, it's just a bit of trig. But I'm wondering how one would find a. I understand the slit width has to be comparable to the wavelength for diffraction to occur, but I'm wondering if this question demands something a little more methodical.

Many thanks

-- Yeah I got 3.93x10^(-5)m for d and that is correct [/B]
 
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CricK0es said:
and the third bright bands on either side of the central maximum are missing in the pattern.
You'll have to figure out what that means, it will lead to the slit width.
 
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