- #1

- 92

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G -Singlet

F -Triplet

D -Singlet

P -Triplet

S -Singlet

I think it has to do with the pauli exclusion principle but don't really understand the process.

If someone could walk me through why that would be great! (edit: 2 electron case)

- Thread starter Eats Dirt
- Start date

- #1

- 92

- 0

G -Singlet

F -Triplet

D -Singlet

P -Triplet

S -Singlet

I think it has to do with the pauli exclusion principle but don't really understand the process.

If someone could walk me through why that would be great! (edit: 2 electron case)

- #2

- 470

- 58

$$

|j,_z\rangle=|1/2,\pm1/2\rangle\otimes|1/2,\pm1/2\rangle,

$$

where [itex]J=S_1+S_2[/itex] is the total spin. Now, it turns out that, in Quantum Mechanics, when you compose two spin-1/2 states, the total angular momentum can be either J=0 (single) or J=1 (triplet). Most of the times the atomic interaction depends on the total spin of the system and so it turns out that it is determined by the fact that the system is in a single/triplet.

For example, if you have an interaction of the kind:

$$ H=\lambda \vec{S}_1\cdot\vec{S}_2,$$

where [itex]\lambda[/itex] is coupling constant, then you can write:

$$

J^2=(S_1+S_2)^2=S_1^2+S_2^2+2S_1\cdot S_2 \Rightarrow S_1\cdot S_2=\frac{J^2-S_1^2-S_2^2}{2}=\frac{j(j+1)-3/2}{2}.

$$

Then if you are in a single case [itex]j=0[/itex] and the energy shift is given by [itex]\Delta E_{sing}=-(3/4)\lambda[/itex], while if you are in a triplet [itex]j=1[/itex] and [itex]\Delta E_{tripl}=+(1/4)\lambda[/itex].

- #3

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- 0

I still don't quite understand how this connects to the total level L values, for example why does the G state exclusively have a singlet

[tex]

^{2S+1}L_{J}

[/tex]

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