# Singular points in 3-dim space

1. Nov 28, 2006

### firenze

For a linearized system I have eigenvalues $$\lambda_1, \lambda_2 = a \pm bi \;(a>0)$$ and $$\lambda_3 < 0$$,
then it should be an unstable spiral point. As $$t \to +\infty$$ the trajectory will lie in the plane which is parallel with the plane spanned by eigenvectors $$v_1,v_2$$ corresponding to $$\lambda_1, \lambda_2$$.

Right? I am just not very sure.

2. Nov 29, 2006

### HallsofIvy

Yes, that is correct.

3. Nov 29, 2006

Thanks