Hello everyone thanks for giving me your support, sorry if i post in the wrong section. 1. The problem statement, all variables and given/known data What the problem asks for: In the picture we can see the graph of sinusoidal i1=i1(t) and i2=i2(t) It asks for: ν(as i read, it said only one so that's how i went beyond on resolving ecuations)=? φ0=? i1(t1)=? i2(t2)=? φ1=? φ2=? i hope i translate good, phase shifts φ12,φ21 of i2 behind and before of i1 Given data: t1=2,5×10-3(s) t2=5×10-3(s) T2=0,02 Imax1=1,5(A) Imax2=1 http://postimg.org/image/jejwzmzn7/ [Broken] (this is the graph) The attempt at a solution This is what i did i got stuck at phase shifts. i(t)=Imaxsin(ωt+φ) 1.i(t1)=Imax1sin(ωt1+φ1) 2.i(t2)=Imax2sin(ω2+φ2) ω=2π/T or 2πv ν=1/T=> ν=1/T2=>ν=1/2×10-2(s)-1 from here => i(t) becomes 1.i(t1)=Imax1sin(2π/T1t1+φ1) 2.i(t2)=Imax2sin(2π/T2t2+φ2) from here => φ2 i got it out like this: Δt.........Δφ T...........2π => Δφ=(Δt×2π)/T =>2 φ2-φ0=(t2-t1×2π)/T => φ2=(5×10-3-2,5×10-3×2π)/T =>φ2=(2,5×10-3×2π)/1/2×10-2 =>φ2=5×10-5×2π so 2.i(t2)=Imax2sin(2π/T2t2+φ2) i(t2)=sin(2π×1/2×10-2×5×10-3+5×10-5×2π) after this i said that T1 =t2-t1+T2 => (2,5×10-3+2×10-2 =>(4,5×10-5) which got me confused cause if this is different from the other one(T2).... then shouldn't it have to v?