Sinusoidal alternating current/Homework

[ThisVelvetGlove]

Hello everyone thanks for giving me your support, sorry if i post in the wrong section.

1. Homework Statement
What the problem asks for:
In the picture we can see the graph of sinusoidal i₁=i₁(t) and i₂=i₂(t)
It asks for:
ν(as i read, it said only one so that's how i went beyond on resolving ecuations)=?
φ₀=?
i₁(t₁)=?
i₂(t₂)=?
φ₁=?
φ₂=?
i hope i translate good, phase shifts φ₁₂,φ₂₁ of i₂ behind and before of i₁
Given data:
t₁=2,5×10^-3(s)
t₂=5×10^-3(s)
T₂=0,02
I_max1=1,5(A)
I_max2=1
http://postimg.org/image/jejwzmzn7/ (this is the graph)
The attempt at a solution
This is what i did i got stuck at phase shifts.

i(t)=I_maxsin(ωt+φ)

1.i(t₁)=I_max1sin(ωt₁+φ₁)
2.i(t₂)=I_max2sin(ω₂+φ₂)
ω=2π/T or 2πv
ν=1/T=> ν=1/T₂=>ν=1/2×10^-2(s)^-1
from here => i(t) becomes
1.i(t₁)=I_max1sin(2π/T₁t₁+φ₁)
2.i(t₂)=I_max2sin(2π/T₂t₂+φ₂)
from here => φ₂ i got it out like this:
Δt...Δφ
T...2π
=> Δφ=(Δt×2π)/T =>2 φ₂-φ₀=(t₂-t₁×2π)/T
=> φ₂=(5×10^-3-2,5×10^-3×2π)/T
=>φ₂=(2,5×10^-3×2π)/1/2×10^-2
=>φ₂=5×10^-5×2π
so
2.i(t₂)=I_max2sin(2π/T₂t₂+φ₂)
i(t₂)=sin(2π×1/2×10^-2×5×10^-3+5×10^-5×2π)
after this i said that
T₁ =t₂-t₁+T₂
=> (2,5×10^-3+2×10^-2
=>(4,5×10^-5)
which got me confused cause if this is different from the other one(T2)... then shouldn't it have to v?

 

[lightgrav]

If they want 2 distinct φ values, that means one for each curve ... not the difference from one to the other.
(that is, the angle that the sine is offset ... i₂ looks like a cosine, so make sure your units are correct)
They both have the same T, and hence the same ω and same ν (or f) .
the initial time offset does not relate to their repeat time periods.