Sketch and Analyze Range of f(x) = 2sin(x)

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SUMMARY

The function f(x) = 2sin(x) is defined for the domain 0 ≤ x ≤ 180 degrees. The range of this function can be determined by analyzing its graph, which oscillates between 0 and 2. Specifically, f(0) = 0 and f(180) = 0, while the maximum value occurs at f(90) = 2. Therefore, the complete range of f(x) is [0, 2].

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Homework Statement


The function f with domain 0\leqx\leq180
is defined by f(x)=2sinx/Sketch and find the range of f.

Homework Equations





The Attempt at a Solution



well..i haven't got a clue, if i try to get value for 2sin(0) gives me zero and for 2sin(180) gives me the same answer =/.Thanks in advance.
 
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If you sketch the graph of y = 2 sin(x), you should be able to see at a glance the range of this function. Your x values are in degrees, which you should state.

Do you know what the graph of y = sin(x) looks like? The graph of your function is related to this one.
 
ibysaiyan said:

Homework Statement


The function f with domain 0\leqx\leq180
is defined by f(x)=2sinx/Sketch and find the range of f.

Homework Equations





The Attempt at a Solution



well..i haven't got a clue, if i try to get value for 2sin(0) gives me zero and for 2sin(180) gives me the same answer =/.Thanks in advance.
So try numbers between 0 and 180!
 

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