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Sketch graph as function of another

  1. Oct 26, 2011 #1
    Sketch g(t) = f(-3t + 9).

    I know how to work this out with trial and error:

    t = 0 => g(t) = f(9) = 0
    t = 1 => g(t) = f(6) = 0
    t = 2 => g(t) = f(3) = 2
    t = 3 => g(t) = f(0) = -3
    t = 4 => g(t) = f(-3) = 0
    etc...

    How do I do this in a faster and more reliable way, taking into account all the coordinates?
     

    Attached Files:

  2. jcsd
  3. Oct 26, 2011 #2
    I asked around and it turns out I needed to do this visually.

    f(-3t + 9) = f(-3[t-3])

    1. Compress f(x) -> f(3x)
    2. Time reverse f(3x) -> f(-3x)
    3. Time shift f(-3x) -> f(-3x[t-3])
     
  4. Oct 27, 2011 #3

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Since you never told us what "f" was, it was impossible to make sense out of your question or your graph.
     
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