Graph of function of acceleration and velocity after time t

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Homework Help Overview

The discussion revolves around graphing the function of velocity influenced by a constant acceleration. The original poster sets up the problem by defining acceleration as 1 m/s² and seeks to find the velocity at various time points to represent it graphically.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use the equation for velocity under constant acceleration but encounters a discrepancy due to the need for previous outputs. Some participants suggest using a simplified equation for velocity based on initial conditions, while others point out patterns in the changes of velocity over time intervals.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem and clarifying the use of initial conditions. Some guidance has been offered regarding the equation to use for calculating velocity, but no consensus has been reached on the overall approach.

Contextual Notes

There is a mention of confusion regarding the initial conditions and the nature of acceleration, with some participants questioning the assumptions made about the problem setup.

Nano-Passion
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This is out of mere interest, though I'm having trouble figuring it out. Note, I set up this problem myself.

Homework Statement


Say I want to graph the function of velocity v at any given time t influenced by an acceleration a.

Given
a = 1 m/s^2

Find
velocity of any given time and represent it in a graph

Homework Equations



?

The Attempt at a Solution



The way I tried to solve this was by putting time t as the input (x) and velocity v as the output f(x).

I used the equation ( V final = at + v intial ) to find the velocity at any given point in time. But I found a big discrepancy because I need the previous output for the next output.

My table of functions looked something like this:

x | f(x)
--------
1 | 1
2 | 3
3 | 6
4 | 10
10| ?
 
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If v(0) = 0 (Vinitial), then for each t, try using v(t) = at + 0.
 
Notice that between t= 1 and t= 2, velocity has changed from 1 to 3, a change of 2. Between t= 2 and t= 3, velocity has changed from 3 to 6, a change of 3. Between t= 3 and t= 4, velocity has changed from 6 to 10, a change of 4. See the pattern? How much do you think the velocuity will change between t= 4 and t= 5? Add that to 10 to find the velocity at t= 5.

(This is characteristic of a linearly changing acceleration.)

And, by the way, it not necessary that "initial" mean t= 0. Here you could take the "initial postion" to be at t= 1. Then lewando's formula could be written v(t)= a(t-1)+ v(1). Of course lewando's formula assumes a constant acceleration which NOT the case here.
 
Last edited by a moderator:
Nano-Passion said:
Given
a = 1 m/s^2

This is why I thought a was constant. I thought that the function table was something N-P had generated, not part of the original problem statement.
 
lewando said:
If v(0) = 0 (Vinitial), then for each t, try using v(t) = at + 0.

Oh yes, such a silly mistake of me.

Thank you! And sorry for the late reply.
 

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