Sketch the curve with the given polar equation. θ = −pi/6?

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    Curve Polar Sketch
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Discussion Overview

The discussion revolves around the polar equation θ = −π/6, specifically focusing on the nature of the curve it represents. Participants explore the geometric interpretation of this polar equation, considering its implications in a polar coordinate system.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant asserts that the curve is a straight line passing through the origin, questioning whether it slopes like \ or /.
  • Another participant clarifies that the curve consists of all points (r, θ) where θ is −π/6, confirming it is a straight line through the origin making an angle of −π/6 with the polar axis.
  • A subsequent reply indicates an assumption that the line should slope like \ based on the previous clarification.
  • Another participant simply agrees with the previous statements.

Areas of Agreement / Disagreement

Participants generally agree that the curve is a straight line through the origin at an angle of −π/6, but there is some uncertainty regarding the specific orientation of the line.

Contextual Notes

The discussion does not resolve the ambiguity regarding the exact slope direction of the line, as participants express differing interpretations.

carl123
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Sketch the curve with the given polar equation. θ = −pi/6?

I know for certain that its a straight line that passes through the origin but what I'm not sure is if its like this \ or like this /
 
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This curve consists of all points $(r, \theta )$ such that the polar angle $\theta$ is $-\frac{\pi}{6}$.
It is the straight line that passes through the origin $O$ and makes an angle of $-\frac{\pi}{6}$ with the polar axis.
 
mathmari said:
It is the straight line that passes through the origin $O$ and makes an angle of $-\frac{\pi}{6}$ with the polar axis.

Thanks for your reply, by what you said, I'm assuming the line should be like this \ then
 
Yes. (Yes)
 
Ok, thanks
 

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