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**1. The problem statement, all variables and given/known data**

The problem is shown as a picture, but here it is in word form: A straight line with a negative slope intersects the point 2,1. The area under this line in quadrant one of the cartesian grid is 4. What is the slope of this line?

**2. Relevant equations**

Area of a triangle: A=0.5bh

Point-Slope formula: y-y1=m(x-x1)

Slope: m=(y2-y1)/(x2-x1)

**3. The attempt at a solution**

I wrote a lot of equations that met the criterion of passing through the point 2,1 and having a negative slope, and calculated the area of the triangle the line created in quadrant one. I came to the solution this way - m=-0.5. However, I want to find a more elegant way of approaching this solution.

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