(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The problem is shown as a picture, but here it is in word form: A straight line with a negative slope intersects the point 2,1. The area under this line in quadrant one of the cartesian grid is 4. What is the slope of this line?

2. Relevant equations

Area of a triangle: A=0.5bh

Point-Slope formula: y-y1=m(x-x1)

Slope: m=(y2-y1)/(x2-x1)

3. The attempt at a solution

I wrote a lot of equations that met the criterion of passing through the point 2,1 and having a negative slope, and calculated the area of the triangle the line created in quadrant one. I came to the solution this way - m=-0.5. However, I want to find a more elegant way of approaching this solution.

**Physics Forums - The Fusion of Science and Community**

# Slope of line based on one point and area of triangle

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Slope of line based on one point and area of triangle

Loading...

**Physics Forums - The Fusion of Science and Community**