Solve for the slope and length of a line segment

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SUMMARY

The discussion focuses on solving for the slope (m) and length of the hypotenuse of a right triangle defined by a shaded area of 4. The key points include the use of the area formula A = 1/2 * base * height and the point-slope formula y - y1 = m(x - x1). Participants suggest deriving relationships between the x-intercept (a) and y-intercept (b) to express the area in terms of these variables, allowing for the calculation of both the slope and length of the hypotenuse.

PREREQUISITES
  • Understanding of right triangle properties
  • Familiarity with the area formula A = 1/2 * base * height
  • Knowledge of the point-slope formula in coordinate geometry
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Learn how to derive the slope of a line using two points
  • Study the relationship between intercepts and area in coordinate geometry
  • Explore methods for solving systems of equations
  • Investigate the Pythagorean theorem for calculating hypotenuse lengths
USEFUL FOR

Students studying geometry, educators teaching coordinate geometry, and anyone interested in solving algebraic problems involving slopes and areas of triangles.

Husaaved
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The problem is to a.) solve for the slope m of the hypotenuse of the right triangle indicated by the shaded area, and b.) solve for the length of the hypotenuse, if possible. I made a mistake in transcribing the problem onto paper, the line of course extends indefinitely but the shaded area and the length of the line bounded by the y- and x-axes are all that are of interest.

The area of the shaded area is 4, and a single point along the line are all that is given. I get also that a (0, y) and (x, 0) are also given, and I know that the point-slope formula is y - y1 = m(x - x1, but I'm not sure in what way to apply this information to the problem.

Any thoughts?
 
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Husaaved said:
Pmb61gZ.jpg


The problem is to a.) solve for the slope m of the hypotenuse of the right triangle indicated by the shaded area, and b.) solve for the length of the hypotenuse, if possible. I made a mistake in transcribing the problem onto paper, the line of course extends indefinitely but the shaded area and the length of the line bounded by the y- and x-axes are all that are of interest.

The area of the shaded area is 4, and a single point along the line are all that is given. I get also that a (0, y) and (x, 0) are also given, and I know that the point-slope formula is y - y1 = m(x - x1, but I'm not sure in what way to apply this information to the problem.

Any thoughts?

There are two pieces of information given, the area and a point on the line. A good starting point would be to write down the area in terms of a formula. ##A=\frac{1}{2}bh##.

You have two unknowns, so you need another equation so you can substitute variables to solve for the other.

Think about slope.

Edit: That might have been too vague. How can you relate x and y together using slope? Then use that relationship in the area formula to solve for x and y.
 
Last edited:
Husaaved said:
The problem is to a.) solve for the slope m of the hypotenuse of the right triangle indicated by the shaded area, and b.) solve for the length of the hypotenuse, if possible. I made a mistake in transcribing the problem onto paper, the line of course extends indefinitely but the shaded area and the length of the line bounded by the y- and x-axes are all that are of interest.

The area of the shaded area is 4, and a single point along the line are all that is given. I get also that a (0, y) and (x, 0) are also given, and I know that the point-slope formula is y - y1 = m(x - x1, but I'm not sure in what way to apply this information to the problem.

Any thoughts?

You know x1=2 and y1=1. Plug in these data into the formula y-y1=m(x-x1) *

Denote the X-intercept by a and the Y intercept by b. How do you get the shaded area in terms of a and b?

You get equations for a and b in terms of m by substituting (a,0) and (0,b) into eq. *.
 

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