Smallest Heat of Combustion: Cyclopentane

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Discussion Overview

The discussion revolves around identifying which isomer of C5H10 has the smallest heat of combustion, specifically focusing on cyclopentane and its structural isomers. The conversation includes theoretical considerations of stability, bond formation, and enthalpy changes related to combustion.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant suggests that cyclopentane (A) should have the smallest heat of combustion due to its lack of substituent groups.
  • Another participant challenges this by indicating that the reasoning is based on guessing and suggests considering heats of formation of bonds and hydrocarbons.
  • A claim is made that cis-1,2-dimethylcyclopropane has a larger negative heat of combustion than trans-1,2-dimethylcyclopropane, attributing this to the bond angles in cyclopropane.
  • One participant humorously asserts that cyclopentane is definitely the answer based on research.
  • A later post revises the initial claim, proposing that 1,1-dimethylcyclopropane (C) would have the smallest heat of combustion due to its instability from the proximity of the two methyl groups.
  • A question is raised about the relationship between bond stability and heat of combustion, asking if easier breakage leads to a smaller heat of combustion.
  • Another participant provides a technical explanation about enthalpy changes during combustion, mentioning the role of ring strain in methylcyclobutane and comparing it to cyclopentane's enthalpy of formation.

Areas of Agreement / Disagreement

Participants express differing views on which isomer has the smallest heat of combustion, with no consensus reached. Various factors such as stability, bond strain, and enthalpy of formation are debated without resolution.

Contextual Notes

The discussion involves assumptions about the stability of isomers and their heats of formation, which are not fully explored or defined. The relationship between bond strength and heat of combustion remains ambiguous among participants.

ilovephysicssomuch
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Which isomer of C5H10 would you expect to have the smallest heat of combustion?
A. cyclopentane
D. cis-1,2-Dimethylcyclopentane
E. trans-1,2-Dimethylcyclopentane

.. I'm thinking A because there are no groups.. can I please be confirmed?o:)
 
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I will confirm to you that you are guessing, then I'll throw you a bone. Somewhere in your text or class notes, you've been given information on heats of formation of bonds (C-C σ, C-C &pi, C-H), or heats of formation of hydrocarbons (alkenes, alkanes). Give you something to think on?
 
Well...

cis-1,2-dimethylcyclopropane has a larger negative heat of combustion than trans-1,2-Dimethylcyclopropane.

The c-c bonds in cyclopropane are bent... which makes for weaker bonds.. so now its E
 
haha I am just messing with you.. It's Definitely A.. According to research =P
 
Ok.. Final Answer...

I changed my mind.. to have the smallest heat of combustion, the compound must be the least stable..
and if we had 5 choices:
A) Cyclopentane
B) Methylcyclopropane
C)1,1-Dimethylcyclopropane
D) cis-1,2-dimethylcyclopropane
E) trans-1,2-Dimethylcyclopropane

C) would have the smallest heat of combustion because it is least stable...
due to the interaction of the two methyl groups... that are located CLOSEST together...
hmmm.. is that a good reasoning? So.. C)1,1-Dimethylcyclopropane
 
EASY TO BREAK = SMALLEST HEAT OF COMBUSTION? is that true?:confused:
 
You're thinking about the right things, but you came up just slightly backward for a result. Everything winds up at the same enthalpy when it's combusted, carbon dioxide plus water in the same stoichiometry. Now how do the starting enthalpy levels compare to one another? Methylcyclobutane has a lot of ring strain, enough so that it has a positive enthalpy of formation relative to hydrogen and carbon. Cyclopentane is slightly strained, but not much, and has a negative enthalpy of formation. Formation of water and carbon dioxide from oxygen and these two isomers is accompanied by an enthalpy change that is the difference between h-carbon plus oxygen and water plus carbon dioxide. Given that the enthalpies of formation of water and carbon dioxide are large and negative, which is the larger difference?
 

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